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How long does it take for a golf ball to fall from rest for a distance of 11.8 m?

(a) How long does it take for a golf ball to fall from rest for a distance of 11.8 m? (b) How far would the ball fall in twice that time?

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Comments

3 Responses to “How long does it take for a golf ball to fall from rest for a distance of 11.8 m?”
  1. Ben C says:
    April 12, 2012 at 3:25 pm

    Use the equation s = ut + ½at².

    s is distance
    u is initial velocity (zero)
    a is gravitational acceleration
    t is the time that you are trying to find

  2. stmc says:
    April 13, 2012 at 1:03 pm

    x=1/2at^2
    -11.8m = 1/2(-9.8m/s^2)t^2
    t= 1.55s

    1.55s x 2= 3.1s

    x=1/2at^2
    x= 1/2(-9.8m/s^2)(3.1s)^2
    x= -47.1m

    the negative means downward.

  3. dhaminator says:
    April 15, 2012 at 5:16 am

    Write down this equation

    a)

    d=(1/2)at^2
    11.8=(1/2)(9.8)t^2
    2.4=t^2
    1.55s=t

    b)

    d=(1/2)at^2
    d=(1/2)(9.8)(2*1.55)^2
    d=47.1m

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